forked from fishercoder1534/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path_1021.java
68 lines (66 loc) · 2.48 KB
/
_1021.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.List;
/**1021. Remove Outermost Parentheses
*
* A valid parentheses string is either empty (""), "(" + A + ")", or A + B, where A and B are valid parentheses strings, and + represents string concatenation. For example, "", "()", "(())()", and "(()(()))" are all valid parentheses strings.
*
* A valid parentheses string S is primitive if it is nonempty, and there does not exist a way to split it into S = A+B, with A and B nonempty valid parentheses strings.
*
* Given a valid parentheses string S, consider its primitive decomposition: S = P_1 + P_2 + ... + P_k, where P_i are primitive valid parentheses strings.
*
* Return S after removing the outermost parentheses of every primitive string in the primitive decomposition of S.
*
*
* Example 1:
* Input: "(()())(())"
* Output: "()()()"
* Explanation:
* The input string is "(()())(())", with primitive decomposition "(()())" + "(())".
* After removing outer parentheses of each part, this is "()()" + "()" = "()()()".
*
* Example 2:
* Input: "(()())(())(()(()))"
* Output: "()()()()(())"
* Explanation:
* The input string is "(()())(())(()(()))", with primitive decomposition "(()())" + "(())" + "(()(()))".
* After removing outer parentheses of each part, this is "()()" + "()" + "()(())" = "()()()()(())".
*
* Example 3:
* Input: "()()"
* Output: ""
* Explanation:
* The input string is "()()", with primitive decomposition "()" + "()".
* After removing outer parentheses of each part, this is "" + "" = "".
*
* Note:
*
* S.length <= 10000
* S[i] is "(" or ")"
* S is a valid parentheses string
* */
public class _1021 {
public static class Solution1 {
public String removeOuterParentheses(String S) {
List<String> primitives = new ArrayList<>();
for (int i = 1; i < S.length(); i++) {
int initialI = i - 1;
int left = 1;
while (i < S.length() && left > 0) {
if (S.charAt(i) == '(') {
left++;
} else {
left--;
}
i++;
}
primitives.add(S.substring(initialI, i));
}
StringBuilder sb = new StringBuilder();
for (String primitive : primitives) {
sb.append(primitive.substring(1, primitive.length() - 1));
}
return sb.toString();
}
}
}