-
Notifications
You must be signed in to change notification settings - Fork 23
/
973. K Closest Points to Origin.java
executable file
·81 lines (61 loc) · 1.99 KB
/
973. K Closest Points to Origin.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
M
tags: Heap, Sort, Divide and Conquer
time: O(klogk)
space: O(k)
#### PriorityQueue
- Create customized Point{} class
- Sort by distance
- Maintain queue size <= K
#### Divide and Conquer
- ?, select sort?
```
/*
We have a list of points on the plane. Find the K closest points to the origin (0, 0).
(Here, the distance between two points on a plane is the Euclidean distance.)
You may return the answer in any order. The answer is guaranteed to be unique (except for the order that it is in.)
Example 1:
Input: points = [[1,3],[-2,2]], K = 1
Output: [[-2,2]]
Explanation:
The distance between (1, 3) and the origin is sqrt(10).
The distance between (-2, 2) and the origin is sqrt(8).
Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin.
We only want the closest K = 1 points from the origin, so the answer is just [[-2,2]].
Example 2:
Input: points = [[3,3],[5,-1],[-2,4]], K = 2
Output: [[3,3],[-2,4]]
(The answer [[-2,4],[3,3]] would also be accepted.)
Note:
1 <= K <= points.length <= 10000
-10000 < points[i][0] < 10000
-10000 < points[i][1] < 10000
*/
class Solution {
class Point {
int x, y, distance;
public Point(int x, int y) {
this.x = x;
this.y = y;
this.distance = x * x + y * y;
}
}
public int[][] kClosest(int[][] points, int K) {
if (points == null || K < 0 ) return new int[][]{};
PriorityQueue<Point> queue = new PriorityQueue<>(
Comparator.comparing((Point p) -> p.distance).reversed());
for (int[] point : points) {
queue.offer(new Point(point[0], point[1]));
if (queue.size() > K) queue.poll();
}
return buildResult(queue);
}
private int[][] buildResult(PriorityQueue<Point> queue) {
int[][] result = new int[queue.size()][2];
while(!queue.isEmpty()) {
Point p = queue.poll();
result[queue.size()] = new int[]{p.x, p.y};
}
return result;
}
}
```