74.md

题目要求

linux系统 /home目录下有一个文件test.xml，内容如下：

<configuration>
    <artifactItems>
        <artifactItem>
       <groupId>zzz</groupId>
       <artifactId>aaa</artifactId>
    </artifactItem>
    <artifactItem>
       <groupId>xxx</groupId>
       <artifactId>yyy</artifactId>
    </artifactItem>
    <!-- </artifactItem><groupId>some groupId</groupId>
       <version>1.0.1.2.333.555</version> </artifactItem>-->
    </artifactItems>
</configuration>

请写出shell脚本删除文件中的注释部分内容，获取文件中所有artifactItem的内容，并用如下格式逐行输出： artifactItem:groupId:artifactId:aaa

参考答案

#!/bin/bash
#这个脚本用来格式化xml文件
#作者：猿课-阿铭 www.apelearn.com
#日期：2018-12-11

sed '/<!--.*-->/d' test.xml > test2.xml
egrep -n '<!--|\-\->' test2.xml |awk -F ':' '{print $1}' > /tmp/line_number1.txt
n=`wc -l /tmp/line_number1.txt|awk '{print $1}'`
n1=$[$n/2]
for i in `seq 1 $n1`
do
    j=$[$i*2]
    k=$[$j-1]
    x=`sed -n "$k"p /tmp/line_number1.txt`
    y=`sed -n "$j"p /tmp/line_number1.txt`
    sed -i "$x,$y"d test2.xml
done

grep -n 'artifactItem>' test2.xml |awk '{print $1}' |sed 's/://' > /tmp/line_number2.txt
n2=`wc -l /tmp/line_number2.txt|awk '{print $1}'`

get_value(){
    sed -n "$1,$2"p test2.xml|awk -F '<' '{print $2}'|awk -F '>' '{print $1,$2}' > /tmp/value.txt
    
    cat /tmp/value.txt|while read line
    do
        x=`echo $line|awk '{print $1}'`
        y=`echo $line|awk '{print $2}'`
        echo artifactItem:$x:$y
    done
}

n3=$[$n2/2]
for j in `seq 1 $n3`
do
    m1=$[$j*2-1]
    m2=$[$j*2]
    nu1=`sed -n "$m1"p /tmp/line_number2.txt`
    nu2=`sed -n "$m2"p /tmp/line_number2.txt`
    nu3=$[$nu1+1]
    nu4=$[$nu2-1]
    get_value $nu3 $nu4
done