Leetcode Problem 1480 Running Sum of 1d Array.txt

1480. Running Sum of 1d Array
Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

Return the running sum of nums.


Example 1:

Input: nums = [1,2,3,4]
Output: [1,3,6,10]
Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].
Example 2:

Input: nums = [1,1,1,1,1]
Output: [1,2,3,4,5]
Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].
Example 3:

Input: nums = [3,1,2,10,1]
Output: [3,4,6,16,17]



class Solution:
    def runningSum(self, nums: List[int]) -> List[int]:
        idx = 1
        while idx <= len(nums) - 1:
            nums[idx] = nums[idx] + nums[idx - 1]
            idx += 1
        return nums