JS对APP版本号的比较

[akeymo]

思路就是将版本号的每一位拆分成数组，然后从最大位开始比较。如果大于就返回1，小于返回-1，等于返回0。

function compare(version1, version2) {
    if (!version1 || !version2) return false;

    const arr1 = version1.split('.');
    const arr2 = version2.split('.');
    const len1 = arr1.length;
    const len2 = arr2.length;
    const minLen = Math.min(len1, len2);

    let i = 0;
    for (i; i < minLen; i++) {
        const a = parseInt(arr1[i]);
        const b = parseInt(arr2[i]);
        if (a > b) return 1;
        if (a < b) return -1;
    }

    if (len1 > len2) {
        for (let j = i; j < len1; j++) {
            if (parseInt(arr1[j]) !== 0) return 1;
        }

        return 0;
    } else if (len1 < len2) {
        for (let j = i; j < len1; j++) {
            if (parseInt(arr2[j]) !== 0) return -1;
        }

        return 0;
    }

    return 0;
}