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all(..)
Currently, this just lifts the entire expression without any checks on soundness.
Needs to be investigated in detail.
The text was updated successfully, but these errors were encountered:
It is unsound when you can prove all(a -> b):
all(a -> b)
fn test_all all(a -> b) { x : all(a); return x; } fn test_absurd true -> a { use test_all; x : true; let y = test_all(x) : a; return y; }
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Currently, this just lifts the entire expression without any checks on soundness.
Needs to be investigated in detail.
The text was updated successfully, but these errors were encountered: