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GET_SUCCESSOR_PREDESESSOR.PY
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GET_SUCCESSOR_PREDESESSOR.PY
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# INPUT - Tree1() , node=30
# OUTPUT - 60,70
# Explanation - print successor and predesessor
# -----------------------------------------------------------------------------------
# this is just for understanding you don't have to print
# 10
# / | \
# 20 [30] 40
# / \ / | \ \
# 50 [60] [70] 80 90 100
# / \
# 110 120
# -----------------------------------------------------------------------------------
# This is node class which have data children and parent as instance
class TreeNode:
def __init__(self,data=None):
self.data = data
self.childrens = []
self.parent = None
# here in this function will add child
def add_child(self,child):
# make me parent of my child
child.parent = self
# add my child
self.childrens.append(child)
def get_level(self):
# if there is not parent return 0
if not self.parent:
return 0
# add 1 to it so at last will get our ans
return 1+self.parent.get_level()
def print_tree(self):
if self:
# here this is only for decoration
space = self.get_level()*2
if self.parent:
patterns = space*" " + "|_"
else:
# if there is root then it does not have any parent so there is no need to add space and other styling
patterns = ""
print(patterns + str(self.data))
for children in self.childrens:
children.print_tree()
# for finding total nodes present in tree
def total_nodes(self,sum_node):
if not self.childrens:
return sum_node
else:
for children in self.childrens:
sum_node = 1+children.total_nodes(sum_node)
return sum_node
def build_tree(arr):
stack = []
root=TreeNode()
for i in arr:
if i==-1:
stack.pop()
else:
if stack:
new_node = TreeNode(i)
parent_node = stack[-1]
parent_node.add_child(new_node)
stack.append(new_node)
else:
root = TreeNode(i)
stack.append(root)
return root
# Here what we do is we know the recursion that it runs and returns something and value changes after each steps
# so for saving value what we do is make states
# if state ==0 we save the predecessor and after finding data increase state to 1 so will get last node as predecessor
# if state ==1 then will find predecessor so there is one thing one is successor so will save successor that's it
# notice will not perform any operation after will match data with node because we don't want that we only want node after that and before that
def get_successor_predecessor(tree,node):
global successor,predecessor,state
if state==0:
if tree.data == node:
state = 1
else:
predecessor = tree
elif state==1:
successor = tree
state = 2
for child in tree.childrens:
get_successor_predecessor(child,node)
if __name__ == '__main__':
arr = [10,20,50,-1,60,-1,-1,30,70,-1,80,110,-1,120,-1,-1,90,-1,-1,40,100,-1,200,-1,-1]
successor = 0
predecessor = 0
state = 0
tree = build_tree(arr)
lsit = get_successor_predecessor(tree,30)
print("pre",predecessor.data,"suc",successor.data)