reverse-integer-leetcode-7.java

class Solution {
    public int reverse(int x) {
        int reversed =0;
        int pop;
        
        while(x!=0){
            pop = x % 10;
            x/=10;
            
            if(reversed > Integer.MAX_VALUE/10 || reversed == Integer.MAX_VALUE/10 && pop > 7){
                return 0;
            }
            if(reversed < Integer.MIN_VALUE/10 || reversed == Integer.MIN_VALUE/10 && pop < -8){
                return 0;
            }
            
            reversed = (reversed * 10) + pop;
            
            
        }
        return reversed;
    }
}