README_EN.md

434. Number of Segments in a String

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Description

You are given a string s, return the number of segments in the string. 

A segment is defined to be a contiguous sequence of non-space characters.

 

Example 1:

Input: s = "Hello, my name is John"
Output: 5
Explanation: The five segments are ["Hello,", "my", "name", "is", "John"]

Example 2:

Input: s = "Hello"
Output: 1

Example 3:

Input: s = "love live! mu'sic forever"
Output: 4

Example 4:

Input: s = ""
Output: 0

 

Constraints:

• 0 <= s.length <= 300
• s consists of lower-case and upper-case English letters, digits or one of the following characters "!@#$%^&*()_+-=',.:".
• The only space character in s is ' '.

Solutions

Python3

class Solution:
    def countSegments(self, s: str) -> int:
        return len(s.split())

class Solution:
    def countSegments(self, s: str) -> int:
        res = 0
        for i in range(len(s)):
            if s[i] != ' ' and (i == 0 or s[i - 1] == ' '):
                res += 1
        return res

Java

class Solution {
    public int countSegments(String s) {
        int res = 0;
        for (String t : s.split(" ")) {
            if (!"".equals(t)) {
                ++res;
            }
        }
        return res;
    }
}

class Solution {
    public int countSegments(String s) {
        int res = 0;
        for (int i = 0; i < s.length(); ++i) {
            if (s.charAt(i) != ' ' && (i == 0 || s.charAt(i - 1) == ' ')) {
                ++res;
            }
        }
        return res;
    }
}

C++

class Solution {
public:
    int countSegments(string s) {
        int res = 0;
        for (int i = 0; i < s.size(); ++i)
        {
            if (s[i] != ' ' && (i == 0 || s[i - 1] == ' '))
                ++res;
        }
        return res;
    }
};

Go

func countSegments(s string) int {
	res := 0
	for i, c := range s {
		if c != ' ' && (i == 0 || s[i-1] == ' ') {
			res++
		}
	}
	return res
}

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