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N-ary Tree Postorder Traversal.md

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Provided Code

public class Node {
    int val;
    List<Node> children;
}

Solution

class Solution {
    public List<Integer> postorder(Node root) {
        List<Integer> list = new ArrayList();
        postorder(root, list);
        return list;
    }

    private void postorder(Node node, List<Integer> list) {
        if (node != null) {
            for (Node n : node.children) {
                postorder(n, list);
            }
            list.add(node.val);
        }
    }
}

Time/Space Complexity

  • Time Complexity: O(n) since we must visit all nodes.
  • Space Complexity: O(log n) on balanced tree. O(n) otherwise.

Notes

The follow-up question asks us for an iterative solution, but there is no benefit to that solution as neither the time or space complexity is improved by solving the problem iteratively.

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