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✅9. 回文数 #65

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bazinga-web opened this issue Jul 20, 2020 · 2 comments
Open

✅9. 回文数 #65

bazinga-web opened this issue Jul 20, 2020 · 2 comments

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@bazinga-web
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9. 回文数

判断一个整数是否是回文数。回文数是指正序(从左向右)和倒序(从右向左)读都是一样的整数。

示例 1:

输入: 121
输出: true

示例 2:

输入: -121
输出: false
解释: 从左向右读, 为 -121 。 从右向左读, 为 121- 。因此它不是一个回文数。

示例 3:

输入: 10
输出: false
解释: 从右向左读, 为 01 。因此它不是一个回文数。

进阶:

你能不将整数转为字符串来解决这个问题吗?

@bazinga-web
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/**
 * @param {number} x
 * @return {boolean}
 */
var isPalindrome = function(x) {
    let str = x.toString()
    let i = 0, j = str.length - 1
    while (i < j) {
        if (str[i] !== str[j]) return false
        i++;
        j--;
    }
    return true
};

@Ray-56
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Ray-56 commented Jul 21, 2020

双指针解

/**
 * @param {number} x
 * @return {boolean}
 */
var isPalindrome = function(x) {
    const str = x.toString();
    let l = 0;
    let r = str.length - 1;
    while (l < r) {
        if (str[l] !== str[r]) return false;
        l++;
        r--;
    }
    return true;
};

@Ray-56 Ray-56 changed the title 9. 回文数 ✅9. 回文数 Jul 21, 2020
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