069--Sqrt(x).md

Implement int sqrt(int x).

Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4
Output: 2
Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.

class Solution(object):
    def mySqrt(self, x):
        """
        :type x: int
        :rtype: int
        """
        '''
        b = str(pow(x, 0.5))
        # p = b.find(".")
        # if p != -1:
        #     b = b[:p]
        return math.floor(float(b))'''
        l, r = 0, x
        while l <= r:
            mid = l + (r-l)//2
            if mid * mid <= x < (mid+1)*(mid+1):
                return mid
            elif x < mid * mid:
                r = mid
            else:
                l = mid + 1