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Suggestion from Martin for file opening function #40

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xiaoliz0 opened this issue Jun 18, 2024 · 1 comment

Contributor

xiaoliz0 commented Jun 18, 2024

def openFile(path, permissions, encoding):
if (encoding != ""):
return open(path, permission, encoding=encoding)
else:
return open(path, permission)'

Contributor Author

xiaoliz0 commented Jun 18, 2024

def checkHospitalStr(hospital):
if(str(hospital) == "0.0"):
return "-"
else:
return hospital

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