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136. 只出现一次的数字 #83

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Geekhyt opened this issue Sep 20, 2021 · 0 comments

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简单

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Geekhyt commented Sep 20, 2021

位运算

一个数和 0 做异或运算等于其本身
一个数和它本身做异或运算等于 0
异或运算满足交换律和结合律

数组中所有元素的异或运算结果就是数组中只出现一次的数字。

const singleNumber = function(nums) {
    let ans = 0
    for (const num of nums) {
        ans ^= num
    }
    return ans
}

时间复杂度：O(n)
空间复杂度：O(1)

Geekhyt added the 简单 label

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