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Wrong amount of superglue for requirements in tailoring recipes #77694

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IdleSol opened this issue Nov 9, 2024 · 1 comment
Open

Wrong amount of superglue for requirements in tailoring recipes #77694

IdleSol opened this issue Nov 9, 2024 · 1 comment
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(S1 - Need confirmation) Report waiting on confirmation of reproducibility

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@IdleSol
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IdleSol commented Nov 9, 2024

Describe the bug

I'm talking about:

  • "id": "armor_kevlar_rigid",
    "type": "requirement",
    "//": "Shaping and attaching a rigid Kevlar plate to something, per 430 g of rigid Kevlar. Time needed is 45 minutes per unit.",
    "qualities": [ { "id": "CUT", "level": 2 } ],
    "components": [ [ [ "rigid_kevlar_plate", 1 ] ], [ [ "super_glue", 1 ] ] ]
  • "id": "armor_paper_lamellar",
    "type": "requirement",
    "//": "Layering paper sheets, cutting holes in them, laminating them with glue, and connecting multiple of resulting plates with cordage, per 162 g of paper. Time needed is 50 minutes per unit.",
    "qualities": [ { "id": "CUT", "level": 2 } ],
    "components": [ [ [ "paper", 50 ] ], [ [ "super_glue", 4 ], [ "bone_glue", 1 ] ], [ [ "cordage_short", 2, "LIST" ] ] ]

According to:

"//": "Any type of all-surface glue. Each unit is 1cm^2 of coverage",
"components": [ [ [ "super_glue", 4 ], [ "bone_glue", 1 ] ] ]

4 units of superglue are spent per 1 square centimeter.

I haven't found an exact size for the kevlar plate. I assume 30 x 60 (similar to Kevlar sheets). So we need 30 x 60 x 4 = 7200 units of glue.

For paper, that's 21 x 30 = 2520. Taking into account the use of 50 sheets: 126 000 2520 x 4 = 10080

But these are maximum values. Assuming that the entire surface is covered with adhesive superglue.

Attach save file

n/a

Steps to reproduce

n/a

Expected behavior

  1. Make the following changes:
  {
    "id": "armor_kevlar_rigid",
    "type": "requirement",
    "//": "Shaping and attaching a rigid Kevlar plate to something, per 430 g of rigid Kevlar.  Time needed is 45 minutes per unit.",
    "qualities": [ { "id": "CUT", "level": 2 } ],
--    "components": [ [ [ "rigid_kevlar_plate", 1 ] ], [ [ "super_glue", 1 ] ] ]
++    "components": [ [ [ "rigid_kevlar_plate", 1 ] ], [ [ "glue_strong", 1, "LIST" ] ] ]
  },
  {
    "id": "armor_paper_lamellar",
    "type": "requirement",
    "//": "Layering paper sheets, cutting holes in them, laminating them with glue, and connecting multiple of resulting plates with cordage, per 162 g of paper.  Time needed is 50 minutes per unit.",
    "qualities": [ { "id": "CUT", "level": 2 } ],
--    "components": [ [ [ "paper", 50 ] ], [ [ "super_glue", 4 ], [ "bone_glue", 1 ] ], [ [ "cordage_short", 2, "LIST" ] ] ]
++    "components": [ [ [ "paper", 50 ] ], [ [ "glue_any", 1, LIST ], [ [ "cordage_short", 2, "LIST" ] ] ]
  },
  1. Increase the amount of glue required
  • or revise the glue consumption per square centimeter
  • or leave it as it is

Screenshots

No response

Versions and configuration

master

Additional context

I admit that the topic title is not a good one.

@IdleSol IdleSol added the (S1 - Need confirmation) Report waiting on confirmation of reproducibility label Nov 9, 2024
@ampersand55
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I haven't found an exact size for the kevlar plate. I assume 30 x 60 (similar to Kevlar sheets).

Your assumption seems to be correct per #54256:

The second reason is that 24"x12" is a commonly available size for Kevlar sheets and rigid panels in real life, (...) Kevlar layered panels are the same as Kevlar sheets - they are just 16 layers thick, sewn together.

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